X^2+45x=550

Solution for X^2+45x=550 equation:

X^2+45X=550

We move all terms to the left:

X^2+45X-(550)=0

a = 1; b = 45; c = -550;
Δ = b2-4ac
Δ = 452-4·1·(-550)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4225}=65$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-65}{2*1}=\frac{-110}{2}
=-55
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+65}{2*1}=\frac{20}{2}
=10
$